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Limechat host mask
Limechat host mask







Block size of each subnet (4 th Octet) = 256 – 192 = 64 (decimal value of 4 th octet with two 1s).įor /26 mask, we will get 1024 subnets, each with 62 hosts, each subnet has block size of 64.Block size of each subnet(3 rd Octet) = 256 – 255 =1 (decimal value of 3rd octet with all 1s).But once you look the example below, things will be clearer. Block size from 3 rd Octet is 1 and Block size from 4 th Octet is 64.To find Block Size, we need to be careful in calculating the block size because block size for 172.16.0.0/26 will be calculated from 3 rd and 4 th octets both.

limechat host mask

Binary value of 3 rd octet is 11111111 and 4 th Octet is 11000000. Below is list of all 256 subnets:īelow is list of range of IP address of these 256 subnets:

  • Block size of each subnet = 256 – 255(decimal value of 3 rd octet with all 1s) = 1įor /24 mask, we will get 256 subnets, each with 254 hosts, each subnet has block size of 1.
  • N = 8, (all 8 bits of 3 rd Octet are borrowed for network portion), so 2 8 = 256 Binary value of 3 rd octet is 11111111 and 4 th Octet is 00000000. Below is list of all 128 subnets.īelow is list of range of IP address of these subnets.:

    limechat host mask

    Block size of each subnet = 256 - 254 = 2įor /23 mask, we will get 128 subnets, each with 510 hosts, each subnet has block size of 2.









    Limechat host mask